How do you find the ordered-pair solution of $y = (\frac{2}{5}) x + 2$ $y=(2/5)x+2$ corresponding to x= -5?

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How do you find the ordered-pair solution of $y = (\frac{2}{5}) x + 2$ $y=(2/5)x+2$ corresponding to x= -5?

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Answer 1 · 2017-07-29T17:43:04

$(x, y) \to (- 5, 0)$ $(x,y)to(-5,0)$

Explanation:

$substitute x = - 5 into the function and evaluate for y$ $"substitute x = - 5 into the function and evaluate for y"$

$rArry=(2/cancel(5)xx-cancel(5)^1)+2$

$color(white)(rArry)=-2+2=0$

$rArr(x,y)to(-5,0)$

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How do you find the ordered-pair solution of $y = (\frac{2}{5}) x + 2$ $y=(2/5)x+2$ corresponding to x= -5?

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Explanation:

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How do you find the ordered-pair solution of $y = (\frac{2}{5}) x + 2$ $y=(2/5)x+2$ corresponding to x= -5?