How do you find the product of ${(a - 4)}^{2}$ $(a-4)^2$ ?

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How do you find the product of ${(a - 4)}^{2}$ $(a-4)^2$ ?

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Answer 1 · 2018-04-12T01:11:00

See a solution process below:

Explanation:

Use this rule for this special case of quadratics:

$(x - y) (x - y) = x^{2} - 2 x y + y^{2}$ $(color(red)(x) - color(blue)(y))(color(red)(x) - color(blue)(y)) = color(red)(x)^2 - 2color(red)(x)color(blue)(y) + color(blue)(y)^2$

Let:

$a$ $color(red)(a)$ replace $x$ $color(red)(x)$

$4$ $color(blue)(4)$ replace $y$ $color(blue)(y)$

${(a - 4)}^{2} \Rightarrow$ $(color(red)(a) - color(blue)(4))^2 =>$

$(a - 4) (a - 4) \Rightarrow$ $(color(red)(a) - color(blue)(4))(color(red)(a) - color(blue)(4)) =>$

$a^{2} - (2 \cdot a \cdot 4) + 4^{2} \Rightarrow$ $color(red)(a)^2 - (2 * color(red)(a) * color(blue)(4)) + color(blue)(4)^2 =>$

$a^{2} - 8 a + 16$ $a^2 - 8a + 16$

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How do you find the product of ${(a - 4)}^{2}$ $(a-4)^2$ ?

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