How do you find the product of ${(c + 6)}^{2}$ $(c+6)^2$ ?

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How do you find the product of ${(c + 6)}^{2}$ $(c+6)^2$ ?

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Answer 1 · 2017-09-01T21:41:49

See a solution process below:

Explanation:

We can use this rule for quadratics to find the product of the term in the problem:

${(x + y)}^{2} = x^{2} + 2 x y + y^{2}$ $(color(red)(x) + color(blue)(y))^2 = color(red)(x)^2 + 2color(red)(x)color(blue)(y) + color(blue)(y)^2$

Substituting $c$ $c$ for $x$ $color(red)(x)$ and $6$ $6$ for $y$ $color(blue)(y)$ gives:

${(c + 6)}^{2} \Rightarrow c^{2} + (2 \cdot c \cdot 6) + 6^{2} \Rightarrow c^{2} + 12 c + 36$ $(color(red)(c) + color(blue)(6))^2 => color(red)(c)^2 + (2 * color(red)(c) * color(blue)(6)) + color(blue)(6)^2 => c^2 + 12c + 36$

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How do you find the product of ${(c + 6)}^{2}$ $(c+6)^2$ ?

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How do you find the product of ${(c + 6)}^{2}$ $(c+6)^2$ ?