How do you find the quotient of $(r+2)/(r+1)div4/(r^2+3r+2)$ ?

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Answer 1 · 2017-04-08T17:42:53

$= (r + 2)^2/4$

$(r + 2)/(r + 1 ) -: 4 / (r^2 + 3 r + 2)$

change a sign $-:$ to * (multiplication) and the location of $4 / (r^2 + 3 r + 2)$

$= (r + 2)/(r + 1 ) * (r^2 + 3 r + 2)/ 4$

factorize $(r^2 + 3 r + 2)$

$= (r + 2)/cancel(r + 1 ) * ((r+ 2)cancel((r + 1)))/ 4$

$= (r + 2)^2/4$

How do you find the quotient of (r+2)/(r+1)div4/(r^2+3r+2)(r+2)/(r+1)div4/(r^2+3r+2)?