How do you find the relative extrema for f(x)=9x2+1x?

1 Answer
Jan 10, 2016

Relative maxima at x= 13 and minima at x= #1/3)

Explanation:

dfdx=91x2. Equating it to 0 , x=±13. f'(x) does not exist at x=0 hence the critical points are 13,0.and+13. For using first derivative test, test the increasing/decreasing behaviour in intervals (,13),and(13,). If f '(x) is positive, then f(x) is increasing and if it is negative, then f(x) is decreasing. Take up any test value say -1 in (,13),-1/6 in (13,0),1/6 in (0, 1/3) and +1 in (13,)

f ' (x) is positive in (,13),

negative in (13,0),
negative in (0,13)and

positive in (13,)

Conclusion is there is a relative maxima at x=13 ( function changes from increasing to decreasing) and relative minima at x= 13 (function changes from decreasing to increasing)