How do you graph $2 x - 3 y = 6$ $2x-3y=6$ using slope intercept form?

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How do you graph $2 x - 3 y = 6$ $2x-3y=6$ using slope intercept form?

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Answer 1 · 2014-12-23T13:42:44

You can first re-arrange your expression by letting $y$ $y$ alone on one side:
$2 x - 3 y = 6$ $2x-3y=6$
$- 3 y = 6 - 2 x$ $-3y=6-2x$
and finally:
$y = \frac{2}{3} x - 2$ $y=2/3x-2$

$\frac{2}{3}$ $2/3$ is the SLOPE. It tells you how the value of $y$ $y$ changes when $x$ $x$ changes. In this case for each change of 1 in $x$ $x$ you have a change of $\frac{2}{3}$ $2/3$ in $y$ $y$ .
$- 2$ $-2$ is the intercept on the $y$ $y$ axis.

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You now have the coordinates of:
1) intercept y axis: $(0, - 2)$ $(0,-2)$
2) intercept x axis: $(3, 0)$ $(3,0)$

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How do you graph $2 x - 3 y = 6$ $2x-3y=6$ using slope intercept form?

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