Question

How do you graph `3x-5y= 10` using the slope and y intercept?

Answer 1

You first work this into a standard form `y=ax+b`

Step 1: `x`'s to the right:
`3x-5y=10->-5y=-3x+10`

Step 2: divide everything by `-5` to get the `y`
`(-5y)/(-5)=(-3x)/(-5)+10/(-5)->y=3/5 x-2`

Now your slope is `3/5` and your `y`-intercept is `-2`

Graphing:
One point is `(0,-2)`, the `y`-intercept
Take any `x`-value and plug it in the equation, let's say `5`
this gives you `y=3/5 *5-2=1`, so `(5,1)`
Draw the line:
graph{0.6x-2 [-10, 10, -5, 5]}