How do you graph #y=-3x+5# using slope intercept form?

2 Answers
Nov 5, 2014

Let us sketch the graph of #y=-3x+5#.

Step 1: Since the #y#-intercept is #5#, plot the point #(0,5)#, which looks like:

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Step 2: Since the slope is #-3#, move 1 unit to the right and 3 units down, so plot the point #(1,2)#, which looks like:

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Step 3: Connect those points by a straight line, which looks like:

enter image source here

The line in green above is the graph of #y=-3x+5#.


I hope that this was helpful.

Nov 5, 2014

The straight line equation written in slope intercept form is #y = mx + b#, in which #m# is the slope, and #b# is the #y#-intercept.

The equation #y = -3x + 5# is in slope intercept form, and represents a straight line in which -3 is the slope, and 5 is the #y#-intercept. In order to determine ordered pairs that can be graphed, substitute any number for #x# and solve for #y#.

If #x# = 0, #y# = 5: Ordered pair = (0, 5)
If #x# = 1, #y# = 2: Ordered pair = (1, 2)
If #x# = 2, #y# = -1: Ordered pair = (2, -1)
If #x# = 3, #y# = -3: Ordered pair = (3, -3)