How do you graph and list the amplitude, period, phase shift for $y = - 3.5 sin (2 x - \frac{π}{2}) - 1$ $y=-3.5sin(2x-pi/2)-1$ ?

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How do you graph and list the amplitude, period, phase shift for $y = - 3.5 sin (2 x - \frac{π}{2}) - 1$ $y=-3.5sin(2x-pi/2)-1$ ?

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Answer 1 · 2018-03-28T02:32:42

Deatiled below.

Explanation:

$y = A sin (B x + C) + D$ $y = A sin(Bx + C) + D$

Given $y = - 3.5 sin (2 x - \frac{π}{2}) - 1$ $y = -3.5 sin(2x - pi/2) - 1$

$A m p l i t u d e = | A | = | - 3.5 | = 3.5$ $Amplitude = |A| = |-3.5| = 3.5$

$Period = 92 π \frac{)}{| B |} = \frac{2 π}{2} = π$ $"Period " = 92pi) / |B| = (2pi) / 2 = pi$

$Phase Shift = \frac{- C}{B} = \frac{\frac{π}{2}}{2} = \frac{π}{4} . (\frac{π}{4} to the right)$ $"Phase Shift " = (-C) / B = (pi/2) / 2 = pi/4. " " (color(blue)(pi/4 " to the right"))$

$"Verical Shift = D = -1$

graph{-3.5 sin(2x - pi/2) - 1 [-10, 10, -5, 5]}

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How do you graph and list the amplitude, period, phase shift for $y = - 3.5 sin (2 x - \frac{π}{2}) - 1$ $y=-3.5sin(2x-pi/2)-1$ ?

1 Answer

Explanation:

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Explanation:

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How do you graph and list the amplitude, period, phase shift for $y = - 3.5 sin (2 x - \frac{π}{2}) - 1$ $y=-3.5sin(2x-pi/2)-1$ ?