How do you graph and solve #| x-3 | >8 #? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Binayaka C. Oct 1, 2016 Solution: #x < -5 or x > 11#. In interval notation: #(-oo, -5) uu(11,oo)# Explanation: 1) #|x-3| > 8 or x-3 > 8 or x> 11# OR 2) #|x-3| > 8 or x-3 < -8 or x < -5# Solution : # x < -5 or x > 11# In interval notation: #(-oo, -5) uu(11,oo)#[Ans] Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 2534 views around the world You can reuse this answer Creative Commons License