Question

How do you graph `f(x) = 2abs x+1`?

Answer 1

When `x >= 0` we have `f(x) = 2abs(x) + 1 = 2x+1`, which is a straight line of slope `2`, starting from `(0, 1)`

When `x <= 0` we have `f(x) = 2abs(x)+1 = -2x+1`, which is a straight line of slope `-2`, ending at `(0, 1)`

So `f(x)` is basically a 'V' shape of slope `+-2` with vertex at `(0, 1)`

graph{abs(2x)+1 [-10.04, 9.96, -2.24, 7.76]}