How do you graph $y=1/2sin2x-1$ ?

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Answer 1 · 2018-06-24T09:36:46

As below.

Standard form of sine function is $y = A sin (Bx - C) + D$

$"Given equation is " y = (1/2) sin 2x - 1$

$A = 1/2, B = 2, C = 0, D = -1$

$Amplitude = |A| = 1/2$

$"Period " = (2pi) / |B| = pi$

$"Phase Shift " = -C / B = 0$

$"Vertical Shift " = D = -1$

graph{(1/2) sin (2x) - 1 [-10, 10, -5, 5]}

How do you graph y=1/2sin2x-1y=1/2sin2x-1?