How do you graph #y=1/2sqrtx#?

1 Answer
Jul 22, 2018

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Please read the explanation.

Explanation:

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Create adata table to generate the graph:

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Observe the graphs given below:

  1. Graph of #color(blue)(y=sqrt(x)#

  2. Graph of #color(red)(y=(1/2)*sqrt(x)#

The radical function: #color(blue)(y=sqrt(x)# is the Parent Function:

The graph of the parent function starts at the origin #(0,0)#

The graph increases gradually.

The general form of the radical function:

#color(red)(y= f(x)=a sqrt[b(x-c)] +d#, where

( i). #color(red)(|a|# will stretch or shrink the graph vertically

( ii), #color(red)(|b|# will stretch or shrink the graph horizontally

(iii). #color(red)(c# will shift the graph left or right.

( iv). #color(red)(d# will shift the graph up or down.

( v). #color(red)(-a# will flip the graph across -axis

( vi). #color(red)(-b# will flip the graph across y-axis

We can compare both the graphs (parent function and the function given) to comprehend the behavior of the graph and the corresponding radical function.

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Hope it helps.