How do you graph y=-1/3cos(x/2)y=13cos(x2)?

1 Answer
Jun 28, 2018

As below.

Explanation:

"Standard form of cosine function is ' y = A cos (Bx - C) + D

"Given : " -(1/3) cos (x/2)

A = -1/3, b = 1/2, C = D = 0

Amplitude = |A| = |-1/3\ = 1/3

"Period " = (2pi) / |B| = (2pi) / (1/2) = 4 pi

No vertical and phase shifts as C = D = 0

graph{-(1/3) cos (x/2) [-10, 10, -5, 5]}