How do you graph $y = \frac{1}{4} cos 3 x$ $y=1/4cos3x$ ?

Question

1916 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-10T02:29:04

As detailed

$y = A cos (B x - C) + D$ $y = A cos (Bx - C) + D$

Given $y = (\frac{1}{4}) cos x$ $y = (1/4) cos x$

$A = \frac{1}{4}, B = 3, C = 0, D = 0$ $A = 1/4, B = 3, C = 0, D = 0$

$A m p l i t u d e = | A | = \frac{1}{4}$ $Amplitude = |A| = 1/4$

$Period = \frac{2 π}{| B |} = \frac{2 π}{3}$ $"Period " = (2pi) / |B| = (2pi)/3$

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

$"Vertical Shift ' = D = 0$

graph{(1/4)cos(3x) [-10, 10, -5, 5]}

How do you graph y=1/4cos3xy=14cos3xy=1/4cos3x?