How do you graph #y=1/4cos3x#?

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Answer 1 · 2018-05-10T02:29:04

As detailed

#y = A cos (Bx - C) + D#

Given #y = (1/4) cos x#

#A = 1/4, B = 3, C = 0, D = 0#

#Amplitude = |A| = 1/4#

#"Period " = (2pi) / |B| = (2pi)/3#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift ' = D = 0#

graph{(1/4)cos(3x) [-10, 10, -5, 5]}