How do you graph #y=1/4sqrt(x-1)+2#, compare to the parent graph, and state the domain and range?
1 Answer
Jan 4, 2018
Explanation:
graph{sqrt(x-1)/4+2 [-10, 10, -5, 5]}
The graph is
I will find the range using Monotony and continuity.
Therefore
#R_f=f(D_f)=f([1,+oo))=[f(1),lim_(xrarr+oo)f(x))# #=#
because
NOTE: