How do you graph $y = 1 - cos x$ $y=1-cosx$ ?

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Answer 1 · 2015-12-23T14:12:37

First, notice that $y = - cos x + 1$ $y=-cosx+1$ .

Recall the graph of the parent function, $y = cos x$ $y=cosx$ .

graph{cos(x) [-7.9, 7.9, -3.95, 3.95]}

Since $y = - cos x$ $y=color(red)(-)cosx$ , reflect the graph over the $x$ $x$ -axis.

graph{-cos(x) [-7.9, 7.9, -3.95, 3.95]}

Now, shift the graph up by $1$ $1$ unit since the full equation is $y = - cos x + 1$ $y=-cosxcolor(red)(+1$ .

graph{-cos(x)+1 [-7.9, 7.9, -3.95, 3.95]}

How do you graph y=1−cosxy=1-cosx?