How do you graph $y = 1 + sin (\frac{1}{2} x)$ $y=1+sin(1/2x)$ ?

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Answer 1 · 2018-03-29T04:18:37

graph{1+sin(1/2x) [-10, 10, -5, 5]}

$sin (x)$ $Sin(x)$ is the original
$sin (x) + 1$ $sin(x)+1$ moves it up one so every y value is moved up 1

$sin (\frac{1}{2} x)$ $sin(1/2x)$ effects the period and it doubles the period of the sine curve from being $2 π$ $2pi$ to $4 π$ $4pi$

As the period $= \frac{2 π}{B}$ $=(2pi)/B$

With B being $A sin (B (x - C)) + D$ $Asin(B(x-C))+D$ or in this case $\frac{1}{2}$ $1/2$

How do you graph y=1+sin(12x) y=1+sin(1/2x)?