How do you graph #y=1+sqrt(x-3)#?

1 Answer
Dec 16, 2016

Graph is inserted. See the vertex (3, 1) at the #larr#end

Explanation:

graph{1+sqrt(x-3)2 [0, 10, -10, 10]}

The equation #(y-1)^2=x-1# representing the parabola of size a = 1/4

and with vertex V(3, 1) is the combined equation to the pair

#y-1=+-sqrt(x-3)#

representing two halves of the parabola.

Here,

As #sqrt(x-3)>=0, x >=3 and y >=1#.

The graph for the other half given by #y = 1-sqrt(x-3)# follows.

graph{1-sqrt(x-3) [0, 10, -10, 10]}