How do you graph $y = - 1 + tan 2 x$ $y=-1+tan2x$ ?

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How do you graph $y = - 1 + tan 2 x$ $y=-1+tan2x$ ?

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Answer 1 · 2016-07-16T08:19:09

To graph $y = - 1 + tan 2 x$ $y=-1+tan 2x$ , we determine the x and y intercepts and then add points that will enable to draw graph for 1 period. See the explanation.

Explanation:

The given equation

$y = - 1 + tan 2 x$ $y=-1+tan 2x$

Set $x = 0$ $x=0$ then solve for $y$ $y$

$y = - 1 + tan 2 x$ $y=-1+tan 2x$

$y = - 1 + tan 2 (0)$ $y=-1+tan 2(0)$

$y = - 1$ $y=-1$
We have the y-intercept at $(0, - 1)$ $(0, -1)$
~~~~~~~~~~~~~~~~~~~~~~~~~

Set now $y = 0$ $y=0$ then solve for $x$ $x$

$y = - 1 + tan 2 x$ $y=-1+tan 2x$
$0 = - 1 + tan 2 x$ $0=-1+tan 2x$

$1 = tan 2 x$ $1=tan 2x$

$arctan (1) = arctan (tan 2 x)$ $arctan (1)=arctan(tan 2x)$

$\frac{π}{4} = 2 x$ $pi/4=2x$

$x = \frac{π}{8}$ $x=pi/8$
We have the x-intercept at $(\frac{π}{8}, 0)$ $(pi/8, 0)$

Other points are $(\frac{π}{4}, + \infty)$ $(pi/4, +oo)$ and $(- \frac{π}{4}, - \infty)$ $(-pi/4, -oo)$

Since the graph of $y = - 1 + tan 2 x$ $y=-1+tan 2x$ is periodic, there will be a repetition of the same graph every $\frac{π}{2}$ $pi/2$ period. Kindly see the graph of $y = - 1 + tan 2 x$ $y=-1+tan 2x$

![Desmos.com]( useruploads.socratic.org )

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How do you graph $y = - 1 + tan 2 x$ $y=-1+tan2x$ ?

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Explanation:

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Science

Math

Humanities

... and beyond

How do you graph y=−1+tan2x y=-1+tan2x?

1 Answer

Explanation:

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Impact of this question

How do you graph $y = - 1 + tan 2 x$ $y=-1+tan2x$ ?