How do you graph $y = 10 sin 2 x$ $y=10sin2x$ ?

Question

2194 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-13T01:44:11

As below.

Standard form of a sine function is $y = A sin (B x - C) + D$ $y = A sin (Bx - C) + D$

$Given : y = 10 sin (2 x)$ $"Given : " y = 10 sin (2x)$

$A = 10, B = 2, C = D = 0$ $A = 10, B = 2, C = D = 0$

$A m p l i t u d e = | A | = 10$ $Amplitude = |A| = 10$

$Period = \frac{2 π}{| B |} = \frac{2 π}{2} = π$ $"Period " = (2pi)/ |B| = (2pi) / 2 = pi$

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

$Vertical Shift = D = 0$ $"Vertical Shift " = D = 0$

graph{10 sin (2x) [-10, 10, -5, 5]}

How do you graph y=10sin2xy=10sin2x?