How do you graph $y = \frac{2}{3} sin (\frac{π}{3} x)$ $y=2/3sin(pi/3x)$ ?

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Answer 1 · 2018-07-25T11:58:30

As below.

Standard form of sine function is $y = A sin (B x - C) + D$ $y = A sin (Bx - C) + D$

Given $y (\frac{2}{3}) sin ((\frac{π}{3}) x)$ $y (2/3) sin ((pi/3)x)$

$A = \frac{2}{3}, B = \frac{π}{3}, C = D = 0$ $A = 2/3, B = pi/3, C = D = 0$

Amplitude $= | A | = \frac{2}{3}$ $= |A| = 2/3$

Period $= \frac{2 π}{\frac{π}{3}} = 6$ $= (2pi)/ (pi/3) = 6$

Phase Shift $= - \frac{C}{| B |} = 0$ $= -C / |B|= 0$

Vertical Shift $= D = 0$ $= D = 0$

graph{(2/3) sin ((pi/3)x) [-10, 10, -5, 5]}

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