How do you graph $y = \frac{2}{3} sin 4 (x - 5)$ $y=2/3sin4(x-5)$ ?

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Answer 1 · 2018-08-05T11:55:33

$Amplitude = \frac{2}{3}$ $"Amplitude" = 2/3$

$Period = \frac{π}{2}$ $"Period" = pi/2$

Standard form of sine function is $y = A sin (B x - C) + D$ $y = A sin(Bx - C) + D$

Given $y = \frac{2}{3} sin (4 x - 20)$ $y = 2/3 sin(4x - 20)$

$A = \frac{2}{3}, B = 4, C = 20, D = 0$ $A = 2/3, B = 4, C = 20, D = 0$

$Amplitude = | A | = \frac{2}{3}$ $"Amplitude" = |A| = 2/3$

$Period = \frac{2 π}{| B |} = \frac{2 π}{4} = = \frac{π}{2}$ $"Period" = (2pi) / |B| = (2pi)/4 = = pi/2$

$Phase Shift = - \frac{C}{B} = - \frac{20}{4} = - 5$ $"Phase Shift" = -C / B = -20 / 4 = -5$ , 5 to the LEFT.

$Vertical Shift = D = 0$ $"Vertical Shift" = D = 0$

graph{2/3 sin(4x - 20) [-10, 10, -5, 5]}

How do you graph y=23sin4(x−5) y=2/3sin4(x-5)?