How do you graph $y = - 2 - sin (x - π)$ $y=-2-sin(x-pi)$ ?

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Answer 1 · 2018-06-19T06:57:43

As below.

Standard form of sine function is $y = A sin (B x - C) + D$ $y = A sin (Bx - C) + D$

$Given y = - sin (x - π) - 2$ $"Given " y = - sin (x - pi) - 2$

$A = - 1, B = 1, C = π, D = - 1$ $A = -1, B = 1, C = pi, D = -1$

$A m p l i t u d e = | A | = | - 1 | = 1$ $Amplitude = |A| = |-1| = 1$

$Period = \frac{2 π}{| B |} = 2 π$ $"Period " = (2pi) / |B| = 2pi$

$Phase Shift \frac{=_{C}}{B} = - \frac{π}{1} = - π, π to the left$ $"Phase Shift " = _C / B = -pi / 1 = -pi, pi " to the left"$

$Vertical Shift = D = - 2$ $"Vertical Shift " = D = -2$

graph{- sin(x - pi) - 2 [-10, 10, -5, 5]}

How do you graph y=−2−sin(x−π) y=-2-sin(x-pi)?