How do you graph $y = 2 - tan (x + \frac{π}{2})$ $y=2-tan(x+pi/2)$ ?

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Answer 1 · 2018-05-06T13:31:06

As shown below.

$y = A tan (B x - C) + D is the standard form of tan function$ $y = A tan (Bx - C) + D " is the standard form of tan function"$

$Given : y = - tan (x + (\frac{π}{2})) + 2$ $"Given : " y = -tan (x + (pi/2)) + 2$

$Amplitude = None for a tan function$ $"Amplitude " = " None for a tan function"$

$"Period ' = (pi) / |B| = pi / 1 = pi$

$"Phase Shift " = -C / B = -(pi/2) / 1 = -pi/2 , " " pi/2" to the left"$

$"Vertical Shift " = D = 2$
graph{-tan(x + (pi/2)) + 2 [-10, 10, -5, 5]}

How do you graph y=2-tan(x+pi/2)y=2−tan(x+π2) y=2-tan(x+pi/2)?