How do you graph: #y = 2^x + 2#?
1 Answer
Mar 15, 2018
Look at the explanation for this is a "how" question.
Explanation:
First you have to know how the equation
It looks like this:
graph{1.5^x [-83.3, 83.35, -41.66, 41.65]}
That is the general shape.
The range of every equation for
Also the point
Also there is always a horizontal asymptote at
Now plug in some points
Now you just shift the whole graph up by 2
This makes the horizontal asymptote at
graph{2^x+2 [-83.3, 83.35, -41.66, 41.65]}