The first term of geometric sequence is 512 and the common ratio is 0.5 what is the 8th term of the sequence?

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Answer 1 · 2018-05-14T18:10:18

The #8^(th) term# of the seqn, is : #a_8=4#

We know that,

the #n^(th) term# of geometric sequeence is:

#a_n=a_1 r^(n-1)#

where #a_1# is first term and #r# is common ratio.

We have, #a_1=512 and r=0.5=1/2#

So, the #8^(th) term# of the seqn, is :

#a_8=a_1(r)^(8-1)#

#:.a_8=512(1/2)^7=512xx1/128=4#