How do you use the geometric sequence formula to find the nth term?

1 Answer
Jan 13, 2015

A geometric sequence is always of the form
t_n=t_"n-1"*rtn=tn-1r

Every next term is rr times as large as the one before.

So starting with t_0t0 (the "start term") we get:
t_1=r*t_0t1=rt0
t_2=r*t_1=r*r*t_0=r^2*t_0t2=rt1=rrt0=r2t0
......
t_n=r^n*t_0tn=rnt0

Answer:
t_n=r^n*t_0tn=rnt0
t_0t0 being the start term, rr being the ratio

Extra:
If r>1r>1 then the sequence is said to be increasing
if r=1r=1 then all numbers in the sequence are the same
If r<1r<1 then the sequence is said to be decreasing ,
and a total sum may be calculated for an infinite sequence:
sum sum=t_0/(1-r)=t01r

Example :
The sequence 1,1/2,1/4,1/8...
Here the t_0=1 and the ratio r=1/2
Total sum of this infinite sequence:
sum=t_0/(1-r)=1/(1-1/2)=2