How do you graph $y = - 2 cos x + 1$ $y=-2cosx+1$ ?

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Answer 1 · 2018-06-25T11:33:01

As below.

Standard form of cosine function is $y = A cos (B x - C) + D$ $y = A cos (Bx - C) + D$

$Given y = - 2 cos x + 1$ $"Given " y = -2 cos x + 1$

$A = - 2, B = 1, C = 0, D = 1$ $A = -2, B = 1, C = 0, D = 1$

$A m p l i t u d e = | A | = | - 2 | = 2$ $Amplitude = |A| = |-2| = 2$

$Period = \frac{2 π}{| B |} = \frac{2 π}{1} = 2 π$ $"Period " = (2pi) / |B| = (2pi) / 1 = 2pi$

$Phase Shift = - \frac{C}{B} = 0$ $"Phase Shift " = -C / B = 0$

$Vertical Shift = D = 1$ $"Vertical Shift " = D = 1$

graph{-2 cos x + 1 [-10, 10, -5, 5]}

How do you graph y=−2cosx+1 y=-2cosx+1?