How do you graph y=32cos(12πx)?

1 Answer
May 4, 2018

As below.

Explanation:

y=Acos(BxC)+D is the standard form

Given y=(32)cos((π2)x)

Amplitude=|A|=32

Period =2π|B|=2ππ2=4

Phase Shift =CB=0

Vertical Shift =D=0

graph{(3/2) cos ((pi/2)x) [-10, 10, -5, 5]}