How do you graph $y = - 3 + 2 cos (x - π)$ $y=-3+2cos(x-pi)$ ?

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Answer 1 · 2018-07-18T02:33:43

As below.

$y = 2 cos (x - π) - 3$ $y = 2 cos (x-pi) - 3$

Standard form of a cosine function is $y = A cos (B x - C) + D$ $y = A cos (Bx - C) + D$

$A = 2, B = 1, C = π, D = - 3$ $A = 2, B = 1, C = pi, D = -3$

$A m p l i t u d e = | A | = 2$ $Amplitude = |A| = 2$

$"Period ' = (2 pi) / |B| = 2pi$

$"Phase Shift " = -C / B = -pi, color(crimson)( pi " to the LEFT")$

$"Vertical Shift " = D = -3$

graph{2 cos (x - pi) - 3 [-10, 10, -5, 5]}

How do you graph y=-3+2cos(x-pi)y=−3+2cos(x−π)y=-3+2cos(x-pi)?