How do you graph #y=3sin4x#? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions 1 Answer sankarankalyanam Oct 5, 2017 #y=3sin4x# graph{3*sin(4x) [-10, 10, -5, 5]} Explanation: #y=a.sin(bx+c)+d# #Amplitude=3# #Period=(2pi)/b=(2pi)/4=pi/2# #Phase# shift #=c/b=0# #Vertical# shift #d=0# Answer link Related questions How do you graph sine and cosine functions when it is translated? How do you graph #y=sin ( x -frac{\pi}{2} )#? How do you draw a sketch of #y = 1 + cos (x - pi)# How do you shift and graph #y=-3+sinx#? How do you graph #y=3sin(1/3x+ pi/2)-2#? How do you graph #1/2sin(x-pi)#? How do you graph #-sinx+2#? How do you graph #y=3sin(1/2)x#? How do you graph #y=-2cos((pix)/3)#? How do you graph #y = (1/2)sin(x - pi)#? See all questions in Translating Sine and Cosine Functions Impact of this question 3370 views around the world You can reuse this answer Creative Commons License