How do you graph #y=-3sqrt(x-3)# and compare it to the parent graph?

1 Answer
Mar 19, 2018

There is a procedure to graph funcion.

Explanation:

  1. Define the demain and codomain: #RR_+ rarr RR#
  2. Find the intersection between function and x-axes: solve the equation #y=0#, #x=3#
  3. Calculate the first derivative #y'=-3/(2*√(x-3))#
  4. Calculate #y'=0 rArr# no solution exist
    #(-infty,+infty)# the slope is negative (the value of the function fall) and never change
  5. Calculate the second derivative: #y'=-3/(4(x-3)^(3/2))# and #y''=0 rArr# no solution exist
    if #y''>0 # the function is convex (is smiling)
    if #y''<0 # the function is concave (is sad)
    #y'' #is negative #rArr# concave
    enter image source here
    The parent graph is #c√(a*x+b)# where a,b,c are parameters.
    a, c tight or strech, b translate the funcion