How do you graph $y = 3 tan (\frac{1}{2} x) - 2$ $y=3tan(1/2x)-2$ ?

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Answer 1 · 2018-08-02T15:57:01

As below.

$y = 3 tan (\frac{x}{2}) - 2$ $y = 3 tan (x/2) - 2$

Standard form of tangent function is $y = A tan (B x - C) + D$ $y = A tan(Bx - C) + D$

$A = 3, B = \frac{1}{2}, C = 0, D = - 2$ $A = 3, B = 1/2, C = 0, D = -2$

$A m p l i t u d e = N O N E$ $Amplitude = NONE$ for tangent function.

Period $= \frac{π}{| B |} = \frac{π}{\frac{1}{2}} = 2 π$ $= (pi) / |B| = pi / (1/2) = 2pi$

Phase Shift $= \frac{- C}{B} = 0$ $= (-C) / B = 0$

Vertical Shift $= D = - 2$ $= D = -2$

graph{3 tan(x/2) - 2 [-10, 10, -5, 5]}

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