How do you graph $y=4cos(2x+1)$ ?

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Answer 1 · 2017-11-13T22:02:25

The amplitude is 4. The period is $pi$ , it's shifted left 1 unit.

The leading scalar is the amplitude.

The period is found by ${2pi}/B$ . In this case your B value is 2.

The phase shift is the +1, which reverses, so you start the graph one unit to the left.

How do you graph y=4cos(2x+1) y=4cos(2x+1)?