How do you graph $y = 4 sin (2 x - \frac{π}{2})$ $y=4sin(2x-pi/2)$ ?

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How do you graph $y = 4 sin (2 x - \frac{π}{2})$ $y=4sin(2x-pi/2)$ ?

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Answer 1 · 2015-04-18T13:14:22

Your function is a sine function with amplitude $4$ $4$ and starting (at $x = 0$ $x=0$ ) with a value of $- 4$ $-4$ ( $= 4 sin (- \frac{π}{2})$ $=4sin(-pi/2)$ ):
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How do you graph $y = 4 sin (2 x - \frac{π}{2})$ $y=4sin(2x-pi/2)$ ?

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How do you graph $y = 4 sin (2 x - \frac{π}{2})$ $y=4sin(2x-pi/2)$ ?