Question

How do you graph `y=4sin(3x+pi/4)-1`?

Answer 1

As below.

Explanation:

Standard form of equation is `y = A sin(Bx - C) + D`

Given `y = 4 sin (3x + pi/4) - 1`

`Amplitude = |A| = 4`

`"Period " = (2pi) / |B| = (2pi)/3`

`"Phase Shift " = -C / B = (-pi/4) / 3 = -pi/12, " " (color(blue)((pi/12) " to the left"))`

`"Vertical Shift " = D = -1`

graph{4 sin(3x + (pi/4)) - 1 [-10, 10, -5, 5]}