Question

How do you graph `y=5sin(2x+pi)`?

Answer 1

As below.

Explanation:

`y = A sin (Bx - C) + D` , where

`Amplitude = |A|, " Period " = (2pi)/|B|, " Phase Shift " = (-C) / B, " Vertical Shift " = D`

Given equation is `y = 5 sin (2x + pi)`

`Amplitude = |A| = 5`

`"Period " = (2pi) / |B| = (2pi)/|2| = pi`

`" Phase Shift " = (-C) / B = (-pi) / 2 = -pi/2 " " color(blue)((pi/2 " to the left")`

`" Vertical Shift = D = 0`

graph{5 sin(2x + pi) [-10, 10, -5, 5]}