How do you graph $y=cos(x-pi/2)$ ?

Question

3468 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-13T12:35:08

As below.

Standard form of cosine function is $y = A cos (Bx - C) + D$

$y = cos (x - pi/ 2)$

$A = 1, B = 1, C = pi/2, D = 0$

$Amplitude = |A| = 1$

Period $= (2 pi)/ |B| = (2 pi)/ 1 = 2pi$

Phase shift $= -C / B = (-pi/2) / 1 = -pi/2$ , $color(red)(pi/2)$ to the LEFT.

Vertical Shift $= D = 0$

graph{cos (x-pi/2) [-10, 10, -5, 5]}

How do you graph y=cos(x-pi/2)y=cos(x-pi/2)?