How do you graph $y = cos (x - π) - 3$ $y=cos(x-pi)-3$ ?

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Answer 1 · 2018-05-10T02:26:20

As below

Standard form of cosine function is $y = A cos (B x - C) + D$ $y = A cos (Bx - C) + D$

Given $y = cos (x - π) - 3$ $y = cos (x-pi) - 3$

$A = 1, B = 1, C = π, D = - 3$ $A = 1, B = 1, C = pi, D = -3$

$A m p l i t u d e = | A | = 1$ $Amplitude = |A| = 1$

$Period = P = \frac{2 π}{| B |} = 2 π$ $"Period " = P = (2pi) / |B| = 2pi$

$Phase Shift = - \frac{C}{B} = π, π to the right$ $"Phase Shift " = -C / B = pi, " " pi " to the right"$

$Vertical Shift = D = - 3, 3 down$ $"Vertical Shift " = D = -3, " 3 down"$

graph{cos(x - pi) - 3 [-10, 10, -5, 5]}

How do you graph y=cos(x−π)−3y=cos(x-pi)-3?