How do you graph $y = - sin (\frac{1}{10} x)$ $y=-sin(1/10x)$ ?

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Answer 1 · 2018-05-30T16:20:21

Graph inverted on x axis and stretched to a period of $20 π$ $20pi$

$y = - sin (\frac{1}{10} x)$ $y=-sin(1/10x)$

standard for is:

$y = a sin (b x - c) + d$ $y = asin(bx-c)+d$

a = amplitude, $a < 0$ $a<0$ graph inverts on x axis.

b - horizontal stretch/compression

your c and d are 0

So your graph amplitude $a = - 1$ $a= -1$ so range remains -1 to 1 but the graph is inverted.

your horizontal stretch is $\frac{1}{10}$ $1/10$ so the period of your function will be stretched by a factor of 10:

$10 \cdot 2 π$ $10*2pi$

graph{-sin(1/10x) [-40, 40, -20, 20]}

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