How do you graph $y=-sin2x$ ?

Question

2088 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-13T12:27:45

As below

Standard form of sine function is $y = A cos (Bx - C) + D$

$y = - sin 2x$

$A = -1, B = 2, C = 0, D = 0$

$Amplitude = |A| = 1$

Period $= (2 pi)/ |B| = (2 pi)/ 2 = pi$

Phase shift $= -C / B = 0$

Vertical Shift $= D = 0$

graph{-sin (2x) [-10, 10, -5, 5]}

How do you graph y=-sin2xy=-sin2x?