How do you graph $y = sin 2 x - 2$ $y=sin2x-2$ ?

Question

2774 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-23T22:49:53

graph{sin (2x) - 2 [-10, 10, -5, 5]}

Standard form of equation : $a sin (b x - c) + d$ $a sin(bx - c) + d$
Given equation $y = sin (2 x) - 2$ $y = sin (2x) - 2$

$a = 1, b = 2, c = 0, d = - 1$ $a = 1, b = 2, c = 0, d = -1$

Amplitude $a = 1$ $a = 1$

$P e r i o d = \frac{2 π}{b} = π$ $Period =( 2pi )/ b = pi$

Phase shift $= - (\frac{c}{b}) = 0$ $= -(c/b) = 0$

Vertical shift $= d = - 2$ $= d = -2$

How do you graph y=sin2x-2y=sin2x−2y=sin2x-2?