How do you graph #y=sqrt(2-x# and how does it compare to the parent function?

1 Answer
Nov 1, 2017

#color(red)(y_x=sqrt(2-x))# is the parent function #color(green)(y_(barx)=sqrt(-barx))# shifted 2 units to the right,
which, in turn, is its parent function #color(purple)(y_(hatx)=sqrt(hatx))# reflected through the Y-axis

Explanation:

Note that #color(purple)(hatx)# is the same as #color(green)((-barx))# except that all #color(purple)(hatx)# values are the negative of their corresponding #color(green)(barx)# values. That is #color(green)(-barx)# is the reflection of #color(purple)(hatx)# through the Y-axis.

#color(red)(2-x)# takes every value #color(green)(barx)# and increases it by #color(red)2#, effectively shifting all points 2 units to the right.

Provided you know how to draw #color(purple)y_(hatx)=sqrt(hatx)#
graphing this function should be straight forward if you just perform the reflection and shift.
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