Question

How do you graph `y = sqrt (3x) + 4` by plotting point?

Answer 1

`y=sqrt(3x)+4`
graph{sqrt(3x)+4 [-10.38, 9.62, -5, 5]}

`y=sqrt3x+4`
graph{sqrt3x+4 [-10.38, 9.62, -5, 5]}

Explanation:

1) If given equation is `y=sqrt(3x)+4`
`x=0,y=4`
`x=1,y=sqrt3+4`
`x=2,y=sqrt6+4`
`x=3,y=7`
Four points are `(0,4),(1,5.732),(2,6.449),(3,7)`

2) If given equation is `y=sqrt3*x+4`
Giving values for x, find corresponding value of y from the above equation and plot in a graph.
`x=0,y=4`
`x=1,y=sqrt3+4`
`x=2,y=2sqrt3+4`
`x=-1,y=-sqrt3+4`
Four points are `(0,4),(1,5.732),(2,7.464),(-1,2.268)`