How do you graph #y=sqrt(x-2)+3#?

1 Answer
Jul 28, 2016

See the explanation

Explanation:

Suppose there was an unknown value z

Then #(-z)^2 =z^2" and "(+z)^2=z^2#

So #sqrt(z^2)=+-z#
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So in reality we have #y=+-sqrt(x-2)+3#

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Lets consider the relationship a different way. The above is such that #x# is the independent variable and y the dependant variable. Suppose we reversed this.

Write as # sqrt(x-2)=y-3#

Squaring both sides

#x-2=y^2-6y+9#

#x=y^2-6y+11#

If you plotted this then you would have the same graph as
#y=+-sqrt(x-2)+3#

Tony B

Tony B