How do you graph #y=sqrt(x)+2#?

1 Answer
Oct 10, 2017

The graph should like the square root graph moved upwards two units.

Explanation:

The graph of #sqrtx# is something you should definitely memorize! It looks like this:

graph{sqrtx [-10, 10, -5, 5]}

Logically, what should happen if you add #2# to the right-hand side? The entire graph should be bumped up by #2#, so the final result would look like this:

graph{sqrtx+2 [-10, 10, -5, 5]}

If you're not sure why, let's plug in some points. What happens if we plug in #0# into the given function? You get the point #(0,2)#. Now what happens if we plug in #0# into #sqrtx#? You get the point #(0,0)#. Notice that the y values for the coordinate goes up by two. You can use this method to logically determine how the graph looks.