Question

How do you graph `y=sqrt(x+4)`?

Answer 1

You get hal parabola but along the x axis...have a look:

Explanation:

First of all you need to discover the allowed `x` values for your function, the domain .
The square root can accept all `x` as long as its argument doesn't get negative (you cannot find a real number as solution of a negative square root). You need all the `x` such that:
`x+4>=0` or:
`x>=-4`
Your domain is then all the x bigger or equal to `-4`:

Next we choose "good" values for `x` to be used into our function (are good because they allow to evaluate the square root easily):

`x=-4` then `y=sqrt(0)=0`
`x=-3` then `y=sqrt(1)=1`
`x=0` then `y=sqrt(4)=2`
`x=5` then `y=sqrt(9)=3`
`x=12` then #y=sqrt(16)=4

Plotting these points you get: