How do you graph y=tan2pixy=tan2πx?

1 Answer
Nov 17, 2016

Using the Socratic facility, I have managed to insert the graph for x of small magnitude. Of course, as x to (1/4)_ . y to oo x(14).y and as x to (-1/4)_ + , y to -oox(14)+,y

Explanation:

The period of y=tan kx is pi/kπk. Here, k=2pik=2π and the period is 1/2.

So, choose one period, and a good choice is in (-1/4, 1/4)(14,14).

Using the Socratic facility, I have managed to insert the graph for x

of small magnitude (near 0 ). Of course, as x to (1/4)_ . y to oo x(14).y and as# x

to (-1/4)_ + , y to -oo#

The source for the approximation formula

y=tan 2pix=2pix+(2pix)^3/3y=tan2πx=2πx+(2πx)33, nearly, when x is small, is the Maclaurin series

tan x =x+x^3/3+...

graph{y= 6.28x+82.7x^3 [-10, 10, -5, 5]}