How do you integrate #int (4x - 16) / (x^2 - 2x - 3)# using partial fractions?
How do you integrate #int (4x - 16) / (x^2 - 2x - 3)dx# using partial fractions?
How do you integrate
1 Answer
Sep 4, 2016
OR,
Explanation:
Let
We decompose the Integrand
Using Heavyside's Cover-up Method to find consts.
Hence,
Enjoy Maths.!